Rearranging Algebra Expressions
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Rearranging Algebra Expressions
In each of the following, rearrange the equation listed on the left to isolate z.
| Original Equation (memorize) | Equation for z (memorize) |
|---|---|
| 3 - 5 + 2 = 4 z | z = 0 |
| 5 - 3 + 2 z = 4 | z = 1 |
| 7 z - 3 z + 4 = 0 | z = -1 |
| 8 z - 3 = 4 z + 3 | z = 3/2 |
| z2 + 4 z + 4 = 0 | z = -2 |
| z2 - 6 z+ 9 = 0 | z = 3 |
In each of the following, rearrange the equation listed on the left to isolate Z.
| Original Equation (memorize) | Equation for Z (memorize) |
|---|---|
| A - B = Y × Z | Z = (A - B) / Y |
| A + B = Y + Z | Z = A + B - Y |
| A + B + Y + Z = 0 | Z = -A - B - Y |
| (A × Z) + (B × Y) = 0 | Z = -B × Y / A |
| A = Z × Y / B | Z = B × A / Y |
| A + (Z/Y) = B | Z = (B - A) × Y |
| A + B = sin(Z/Y) | Z = Y × sin-1(A + B) |
| Y = A × cos(Z + B) | Z = -B + cos-1(Y/A) |
| A = B × ZY | Z = (A/B)(1/Y) |
| A = B × exp(Z - Y) | Z = Y + ln(A/B) |
| Y = A / (Z-B)2 | Z = B ± sqrt(A/Y) |
| (Y/A)2 + (Z/B)2 = 1 | Z = ±B × sqrt(1 - (Y/A)2) |
| Question (memorize) | Answer (memorize) |
|---|---|
| A-B=Y×Z | Z=(A-B)/Y |
| A+B=Y+Z | Z=A+B-Y |
| A+B+Y+Z=0 | Z=-A-B-Y |
| (A×Z)+(B×Y)=0 | Z=-B×Y/A |
| A=Z×Y/B | Z=B×A/Y |
| A+(Z/Y)=B | Z=(B-A)×Y |
| A+B=sin(Z/Y) | Z=Y×sin-1(A+B) |
| Y=A×cos(Z+B) | Z=-B+cos-1(Y/A) |
| A=B×ZY | Z=(A/B)(1/Y) |
| A=B×exp(Z-Y) | Z=Y+ln(A/B) |
| Y=A/(Z-B)2 | Z=B±sqrt(A/Y) |
| (Y/A)2+(Z/B)2=1 | Z=±B×sqrt(1-(Y/A)2) |
