Org 1 Review - Reactions of Alkenes
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2012-07-25 12:22
Section 1
| Question | Answer |
|---|---|
| What's Markovnikoff's rule? | Markovnikoff's rule: in the addition of hydrogen halides to alkenes, the nucleophile attaches to the most substituted carbon |
| What's the order of carbocation stability for primary, secondary, and tertiary carbocations? | tertiary carbocation is most stable followed by secondary then primary |
| What's the difference between "dehydration" and "dehydrogenation" | Dehydration is loss of water (H2O). Dehydrogenation is loss of H2. |
| The stability of carbocations increases as the number of carbons attached to the carbon [increases/decreases] | Increases |
| The name for the phenomenon where adjacent p-orbitals line up and delocalize their bonding is called _____. | conjugation |
| A reaction that produces 2-butanol from butene selectively would be called _____selective. | regioselective |
| The reaction of 1-butene with HBr produces 2-bromobutane. Is this an enantioselective reaction? Why/why not? | Not an enantioselective reaction - it goes through a carbocation, which flat, has a mirror plane and is thus achiral. |
| True or false: when you do a hydroboration reaction on a molecule that already has a chiral center, you will form a mixture of enantiomers. | False - you will make a mixture of diastereomers. This is because you already have a chiral center, and your reaction will not invert this - so there's no way you can make a mixture of enantiomers. |
| What is the regioselectivity of the hydroboration reaction? | The regioselectivity of the hydroboration reaction is anti-Markovnikoff (the boron adds to the less substituted end of the double bond) |
| What is the stereochemistry of the hydroboration reaction? | The stereochemistry of the hydroboration reaction is "syn". |
Section 2
| Question | Answer |
|---|---|
| What reaction would you use to produce 1-butanol from 1-butene? | Use hydroboration for this reaction, as you want the alcohol on the less substituted end of the double bond. |
| What is the stereochemistry of the bromination reaction (using Br-Br)? | It's trans - you form a 3-membered ring, and attack onto this gives trans. |
| What's the stereochemistry of additions of hydrogen halides to alkenes? | The stereochemistry is random - you go through a free carbocation, so there is no preferred stereochemistry - nucleophile can attack from either face. |
| The addition of one molecule of H2 to a double bond is called ________. It requires a catalyst in order to occur. The stereochemistry of hydrogenation reactions is ____. | Addition of H2 is called hydrogenation. Stereochemistry is "syn". |
| What are the two key steps in the bromination of an alkene with Br2? | The first step is formation of the 3 membered ring (bromonium ion). The second step is attack of the Br(-) anion to the backside of the most substituted carbon of the bridge, resulting in a trans dibromide. |
| How do the products of the bromination reaction change if you use water as a solvent? | If you use water as solvent, you get attack of the solvent on the bromonium ion instead of Br(–) - (the molecule is reactive and surrounded by the nucleophilic water molecules). The product will have an OH. this is called a halohydrin. |
| What is formed when you treat an alkene with a per-acid, RC(O)OOH [the O in brackets is a carbonyl, C=O] ? | Form an epoxide (oxirane) |
| When HCl is added to 1-propene, the product is 2-chloropropane. Outline the two main steps in this reaction. | Two main steps: the pi bond (double bond) attacks H+, which produces a carbocation. The more substituted carbocation will be produced selectively since it is most stable. Then the carbocation is quenched by reaction with the Cl(-), to give 2-chloropropene. |
| What is the purpose of H2O2 in the hydroboration reaction? | purpose of H2O2 is to oxidize the C-B bond to a C-O bond when the reaction is complete. This is what allows for the formation of alcohols. |
| What is meant by the "more substituted" end of a double bond. | by "more substituted end of double bond" it is generally meant, "the end of the double bond with fewest hydrogens (or most carbons)" |
| True or false - any time you go through a carbocation (or a free radical) the reaction will be stereorandom. | True |
| Let's say you start with 1-butene. If you needed to make 1-butanol, what conditions would you use? If you had to make 2-butanol, what conditions could you use? | To make 1-butanol you need anti-Markovnikoff addition, so you'd use BH3 and H2O2. To make 2-butanol you'd need Markovnikoff addition and thus use either H3O(+) or HgX2 plus water followed by NaBH4. |
| In the bromination of cyclohexene with Br2, you will form two stereoisomers. What will be the relationship of those two stereoisomers? Why do you get a mixture of the two? | The two stereoisomers will be enantiomers. This happens because you will form 50% of the bromonium ions on the top face of the alkene and 50% on the bottom face, and subsequent attack will give you the two enantiomers. |
Org 1 Review - Thermodynamics
Org 1 Review - Free Radicals
Org 1 Review - Reactions of Alcohols
Org 1 Review - Alkynes
Org 1 Review - Substitution and Elimination
Org 1 Review - Reactions of Double Bonds
Org 1 Review - Stereochemistry
Org 1 Review - Conformations
Org 1 Review - Structure and Bonding
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