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Calc 2

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deriboy's version from 2015-09-27 00:07

Section 1

Question Answer
csc(x) =1/sin(x)
sec(x) =1/cos(x)
tan(x) =sin(x)/cos(x)
cot(x) =cos(x)/sin(x) or 1/tan(x)
sin^2(x) + cos^2(x) = 1
1 + cot^2(x) =csc^2(x)
tan^2(x) + 1 = sec^2(x)
1 = sin^2(x) + cos^2(x)
csc^2(x) = 1 + cot^2(x)
sec^2(x) = tan^2(x) + 1
sin(2x) = 2sin(x)cos(x)
sin^2(x) = 1/2 - cos(2x)/2
cos^2(x) = 1/2 + cos(2x)/2
memorize

Section 2

Question Answer
d/dx [sin(x)] = cos(x)
d/dx [cos(x)] = -sin(x)
d/dx [tan(x)] =sec^2(x)
d/dx [csc(x)] = -csc(x)cot(x)
d/dx [cot(x)] = -csc^2(x)
d/dx [sec(x)] =sec(x)tan(x)
memorize

Section 3

Question Answer
∫ tan(x) =ln|sec(x)| + C
∫ cot(x) =ln|sin(x)| + C
∫ sec(x) =ln|sec(x) + tan(x)| + C
∫ csc(x) =ln|csc(x) - cot(x)| + C
memorize