# Ashley Mendizabal

rename
ashleymendizabal's
version from
2016-04-12 21:11

## Section

Question | Answer | |
---|---|---|

circumference | c=2πr c=πd length=cm,m,in,ft units | |

area of a suqare | a=s2 =LxW =BxH units2, cm2, in2, ft2 ,m2 | |

area of an rectangle | a=LxW=BxH units2,cm2,in2,ft2,m2, | |

area of an parallelogram | a=BxH base + height have to meet at 90* units2,cm2,in2,ft2,m2, | |

area of an trapezoid | a= 1/2 H(B+B2) B1+B2 have to be B2 parallel need to meet at 90* | |

area of an circle | a=r2 units2, cm2, m2, in2 ,ft2 | |

radius | line segment from the edge of the circle to the center of the circle r=1/2d line segment from edges going through the center of the d=2r | |

complenentary | 2B that when added =90* | |

supplementary angles | =2anglesS that when added =180* | |

adjacent angles | 2 angle that are next to each other share a vertex | |

vertical anggles | 2 angles S that are oppsite share the same measurement | |

volume of cube | = vlo = LxWxH=S3 , units3,cm,ft3,in3,cubic,units | |

area of an triangle | a=BxH base +height have to meet at 90* units2,cm2,in2,ft2,m2, | |

volume of rectangular | vol= LxWxH units3 ,cm3, ft3, in3, m3 | |

volume of rectangular prism | vol=LxWxH unit3, cm3 ,ft3, in3,m3, | |

volume of triangular prism | vol=area x height =1/2 BxH x height2 | |

volume of cylinder | vol= area x height =πr2H units3, cm3,in3,cubic units | |

Volume of sphere | 3/4 πr3 | |

surface area of a cube | S.A 6s2 | |

surface area of a rectangular prism | S.A= 2a+2b+2c= 2(2.5)+2(5x10)+2(2x10)= 2LW+2H+2HW = 180 units2 | |

surface area of a triangle | P+S+S2+S3 | |

surface area of a quadrilateral | P+S1+S2+S3+S4 | |

surface area of a rectangle | P2L+2W = 2B+2H | |

surface area of a square | P=4s | |

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